ARTS #176 Algorithm 本周选择的题是:Duplicate Emails。 规则 Write an SQL query to report all the duplicate emails. Return the result table in any order. The query result format is in the following example. Soluti...
ARTS #175 Algorithm 本周选择的算法题是:3Sum Closest。 规则 Given an integer array nums of length n and an integer target, find three integers in nums such that the sum is closest to target. Return the sum of the thr...
ARTS #174 Algorithm 本周选择的算法题是:Find K Closest Elements。 规则 Given a sorted integer array arr, two integers k and x, return the k closest integers to x in the array. The result should also be sorted in ascen...
ARTS #173 Algorithm 本周选择的算法题是:Maximum Length of Repeated Subarray。 规则 Given two integer arrays nums1 and nums2, return the maximum length of a subarray that appears in both arrays. Example 1: Input: num...
ARTS #172 Algorithm 本周选择的算法题是:Maximum Score from Performing Multiplication Operations。 规则 You are given two integer arrays nums and multipliers of size n and m respectively, where n >= m. The arrays ar...
ARTS #171 Algorithm 本周选择的算法题是:The Number of Weak Characters in the Game。 规则 You are playing a game that contains multiple characters, and each of the characters has two main properties: attack and defense...
为什么苹果在 Xcode 14 中废弃了 Bitcode 苹果在 Xcode 14 里正式废弃了 Bitcode,从大肆推广到如今落幕,这些年的变化还是挺大的。我们从 Bitcode 的介绍开始说起,尝试探索苹果背后的想法。 什么是 Bitcode Bitcode 是 LLVM bytecode 文件格式,它其实隐含了两个东西: 用于承载 bitstream 的容器 LLVM IR 更通常的说法,是将 Bitcode 称为 LL...
ARTS #170 Algorithm 本周选择的算法题是:Average of Levels in Binary Tree。 规则 Given the root of a binary tree, return the average value of the nodes on each level in the form of an array. Answers within 10-5 of the ...
ARTS #169 Algorithm 本周选择的算法题是:Remove Duplicates from Sorted Array II。 规则 Given an integer array nums sorted in non-decreasing order, remove some duplicates in-place such that each unique element appears a...
ARTS #168 Algorithm 本周选择的算法题是:Split Array into Consecutive Subsequences。 规则 You are given an integer array nums that is sorted in non-decreasing order. Determine if it is possible to split nums into one ...